NOISE LEVEL
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THE
NOISE LEVEL FOR A STACK CAN BE APPROXIMATED BY THE FOLLOWING EQUATION [
API ]
WHERE L100 = NOISE INTENSITY AT 100 ft FROM STACK, dB L = NOISE INTENSITY PARAMETER, WHICH DEPENDS ON PRESSURE RATIO ACROSS THE SAFETY VALVE RELEASING INTO THE STACK HEADER ( RELATION WITH PRESSURE GIVEN BELOW ) M = MASS FLOW RATE THROUGH SAFETY VALVE RELEASING TO FLARE STACK, slugs/Sec. [ 1 slug/Sec. = 32 lb/Sec. ] C = SPEED OF SOUND IN THE WASTE GAS, ft/Sec. = 223 * [ K * T / Mw ]0.5 WHERE K = Cp / Cv OF THE GAS T = GAS TEMPERATURE, O R AND Mw = MOLECULAR WEIGHT OF THE GAS, lb/lb mol. IF Pr = PRESSURE RATIO ACROSS THE SAFETY VALVE = UPSTREAM PRESSURE / DOWNSTREAM PRESSURE OF SAFETY VALVE THEN THE RELATION BETWEEN PRESSURE RATIO AND NOISE INTENSITY PARAMETER, L IS AS FOLLOWS :
SO USING THE ABOVE EQUATIONS, ONE CAN FIND OUT NOISE LEVEL AT 100 ft FROM THE STACK. THE FOLLOWING EQUATION CAN BE USED TO ESTIMATE NOISE LEVEL FOR DISTANCES THAT DIFFER FROM THE 100 ft - REFERENCE BOUNDARY :
WHERE Lp = NOISE LEVEL AT DISTANCE r, dB r = DISTANCE FROM THE SOUND SOURCE, ft L100 = NOISE INTENSITY AT 100 ft FROM STACK,dB EXAMPLE : FOR A FLARE STACK, IF THE MAXIMUM GAS FLOW RATE IS 200,000 lb/Hr., THE PRESSURE RATIO IS 3.0 AND THE GAS TEMPERATURE IS 1500F, WHAT IS THE NOISE LEVEL 400ft FROM FLARE STACK. ASSUME A GAS MOLECULAR WEIGHT OF 54 AND THE K (Cp/Cv) OF 1.1. SOLUTION : SINCE Pr > 2.9, L = 51.9 + 5.06 * Log10Pr SO L = 51.9 + 5.06 * Log10(3.0) = 54.3 FOR T = 1500F = 6100R, C = 223*[ (K*T) / Mw ]0.5 C = 223 * [ 1.1 *610 / 54 ]0.5 = 786 ft / Sec. GAS FLOW RATE = 200,000 lb/Hr.=55.6 lb/Sec. = 1.74 slugs/Sec. SO, L100 = 54.3 + 10 * Log10 [ 0.5 * 1.74 * 7862 ]= 111.6 dB SO, NOISE LEVEL AT A DISTANCE OF 400 ft IS : L400 = 111.6 - 20 * Log10 [ 400 / 100 ] = 99.6 dB.
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